quadratic equations * Kx(x-2)+6=0
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Answer:
Given equation is: kx(x−2)+6=0
kx
2
−2kx+6=0
Then a=k,b=−2k,c=6
Then b
2
−4ac=0
So (−2k)
2
−4k(6)=0
4k
2
−24k=0
4k(k−6)=0
k=0 and k=6
Put value of k
Then 6x
2
−12x+6=0
6x
2
−6x−6x+6=0
6x(x−1)−6(x−1)=0
∴x=1
Step-by-step explanation:
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