Question

Quadratic equations solve 2y²_ y =6

Answer 1

Answer:

we will use quadratic equation i-e y=-b+-√b2_4ac/2a

Step-by-step explanation:

2y2_y=6

subtract 6 on both sides

2y2-y-6=6-6

2y2-y-6=0

a=2,b= -1,c= -6

using quadratic formula

y= -b2+-√b2-4ac/2a

putting values

y=-(-1)2+-√(-1)2-4(2)(-6)/2(2)

= -1+-√-2-48/4

=-1+-√-50)/4

y=-1+√-50/4,y=-1-√-50/4

answer

Answer 2

Step-by-step explanation:

2y²-y=6

2y²-y-6=0

the factors are -4 and 3

2y²-4y+3y-6=0

2y(y-2) +3(y-2)=0

(2y+3) (y-2)=0

either 2y+3=0 or y-2=0

y= -3/2. or y=2.