quadratic equations. solve this
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hey...
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( a - b )x^2 + ( b - c )x + ( c - a ) = 0
roots are equal
( b - c )^2 - 4 ( a - b )( c - a ) = 0
b^2 + c^2 - 2bc + 4 ( a^2 - a( b + c ) + bc ) = 0
4a^2 + b^2 + c^2 - 4ab + 2bc - 4ac = 0
( 2a - b - c )^2 = 0
therefore , 2a - b - c = 0
2a = b + c .
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i hope this helps u.
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.
mark me brainliest plz plz
.
.
( a - b )x^2 + ( b - c )x + ( c - a ) = 0
roots are equal
( b - c )^2 - 4 ( a - b )( c - a ) = 0
b^2 + c^2 - 2bc + 4 ( a^2 - a( b + c ) + bc ) = 0
4a^2 + b^2 + c^2 - 4ab + 2bc - 4ac = 0
( 2a - b - c )^2 = 0
therefore , 2a - b - c = 0
2a = b + c .
.
.
.
i hope this helps u.
.
.
mark me brainliest plz plz
anjali962:
mark me brainliest plz plz
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