Question

| Quadratic Equations
The product of two positive
consecutive integers is 240. Find
them​

Answer 1

Answer:

Step-by-step explanation:

Let the nos be x & x+1

A.T.Q.

=> x^2+x=240

=> x^2+x-240=0

On solving with x = (-b +- √b^2-4ac)/2a

=> x= -16, 15

Since x is a positive integer, x=15.

Therefore the nos. are 15 & 15+1=16

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Answer 2

Step-by-step explanation:

Given

the product of two consecutive positive integer is 240

Formula used

x = -b+√b^2-4ac/2a

x = -b-√b^2-4ac/2a

solution

Let x and x+1 be two consecutive positive integers

x(x+1) = 240

x^2+x -240 = 0

x = -1+√1+960/2

= (-1+31)/2

=30/2 = 15

x = -1-√1+960/2

= (-1-31)/2

=-32/2

=-16 but it is negative... so rejected

hence two consecutive positive integer are 15 and 15+1=16