Math, asked by guptavishal87297, 1 year ago

quadratic eqution 9x^2+6x-4=0​

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Answered by Anonymous
4

Answer:

here is your answer.

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Answered by harshitha202034
0

Answer:

9 {x}^{2}  + 6x - 4 = 0 \\ x =  \frac{ - b± \sqrt{ {b}^{2} - 4ac } }{2a} \\ x =  \frac{ - 6± \sqrt{ {6}^{2} - 4 \times 9 \times ( - 4) } }{2 \times 9}  \\ x =  \frac{ - 6±  \sqrt{36 - ( - 144)} }{18}  \\ x =  \frac{ - 6± \sqrt{36 + 144} }{18} \\ x =  \frac{ - 6±  \sqrt{180}  }{18} \\ x =  \frac{ - 6± \sqrt{36 \times 5} }{18} \\ x =  \frac{ - 6± \sqrt{ {6}^{2} \times 5 } }{18}  \\ x =  \frac{ - 6±6 \sqrt{5} }{18} \\ x =  \frac{ - 6 + 6 \sqrt{5} }{18} \:  \:  \: or \:  \:  \: x =  \frac{ - 6 - 6 \sqrt{5} }{18}  \\  \boxed{ x =  \underline{ \underline{ \frac{ - 1 + \sqrt{5} }{3} }} \:  \:  \: or \:  \:  \: x = \underline{ \underline{  \frac{ - 1 - \sqrt{5} }{3} }}}

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