Quadratic polynomial 2x^2 - 3x + 1 has zeroes alpha and beta . Now form a quadratic polynomial whose zeroes are 3 alpha and 3 beta.
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p(x)=2x^2-3x+1
2x^2-2x-1x+1
2x(x-1)-1(x-1)
(2x-1)(x-1)
x=1/2=α x=1=β
3α=3/2 3β=3
p(x)=x^2-(α+β)x+αβ
=x^2-(3/2+3)x+3/2x3
x^2-7/2x+9/2
2x^2-7x+9
Hope it helps you
Samayraj1234:
How did u get 3a = 3/2 and 3 beta = 3
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