Quadratic polynomial 2x2-3x+1 has zero alpha and betta now former a quadratic polynomial whose zero is 3alpha and 3betta
Answers
Answered by
0
2x^2-3x+1 =0
therefore
sum of zeroes alpha + betta = -b/a
alpha + betta = -(-3)/2
" " = 3/2
now
product of zeroes alpha×betta = c/a
" " = 1/2
now sum of zeros 3alpha+3betta = 3( alpha+ betta)
= 3(3/2) =9/2
now product of zeroes 3alpha ×3betta= 9alpha×betta =9×1/2
= 9/2
now putting into quadratic equation
x^2-sum of zeros x +product of zeroes =0
x^2 -9/2 x+9/2= 0
2x^2-9x +9 = 0 answer
therefore
sum of zeroes alpha + betta = -b/a
alpha + betta = -(-3)/2
" " = 3/2
now
product of zeroes alpha×betta = c/a
" " = 1/2
now sum of zeros 3alpha+3betta = 3( alpha+ betta)
= 3(3/2) =9/2
now product of zeroes 3alpha ×3betta= 9alpha×betta =9×1/2
= 9/2
now putting into quadratic equation
x^2-sum of zeros x +product of zeroes =0
x^2 -9/2 x+9/2= 0
2x^2-9x +9 = 0 answer
Similar questions