Quadratic polynomial 2x² -3x + 1 has zeroes as a and b,then the quadratic polynomial whose zeroes are 3a and 3b is
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Step-by-step explanation:
⇒2x² -3x + 1 =0
⇒2x²-2x-x+1=0
⇒2x(x-1)-1(x-1)=0
⇒(x-1)(2x-1)=0
⇒x=1 or 1/2
let a=1 and b=1/2,
so as per quest. 3a=3 and 3b=3/2
let the required polynomial p(x) has zeros α=3 and β=3/2. now
α+β=9/2 and αβ=9/2
then x²+(α+β)+x-αβ
x²+9/2x-9/2
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