Question

Quadratic polynomial having zeroes 1 and -2 is

Answer 1

Answer:

K [x² + 3)x - 2]

Step-by-step explanation:

Zeroes = 1 and -2

α+β = 1 - 2 = -3

αβ = 1(-2) = -2

Polynomial = K [x² - (α+β)x + αβ]

K is a constant here

= K [x² - (-3)x + (-2)]

= K [x² + 3)x - 2]

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