Question

quadratic polynomial the sum and product of zeros are 1 upon 3, - 1​

Answer 1

heya

Step-by-step explanation:

$sum \: of \: zeroes \: \alpha + \beta = \frac{1}{3}$

$product \: of \: roots \: \alpha \beta = - 1$

$quadratic \: equation \: = {x}^{2} - ( \alpha + \beta )x + \alpha \beta </p><p>[tex] = > {x}^{2} - \frac{x}{3} - 1 = 0$

{$= > 3 {x}^{2} - x - 3 = 0$

hope the answer helps