Question

Quadratic polynomial whose zeroes are -1/2,2/3

Answer 1

Answer:

6x²-x-2

Explanation:

Let m,n are two zeroes of the

Polynomial,

m = -1/2, n = 2/3

i ) m+n = -1/2 + 2/3

= (-3+4)/6

= 1/6

ii ) mn = (-1/2)(2/3)

= -1/3

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Form of quadratic polynomial

whose zeroes are m, n is

k[x²-(m+n)x+mn]

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Now ,

k[x²-(1/6)x-1/3]

For all real values of k it is true.

let k = 6 ,

The polynomial is

6[x²-(1/6)x-1/3]

= 6x²-x-2

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