quadratic polynomial, whose zeroes are -3 and 4,is
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0
Answer:
I think it is↓ by using x^2(sum of zeroes)x+ product of zeroes
Step-by-step explanation:
x^2+x-12
Answered by
0
Answer:
x^2 - x - 12
Step-by-step explanation:
sum of zeroes = - b / a
-3 + 4 = - b / a
1 = - b / a
product of zeroes = c / a
-3 * 4 = c / a
- 12 = c / a
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