Math, asked by ssharada307, 5 months ago

quadratic polynomial,whose zeros r 2 and -8

Answers

Answered by Syamkumarr
2

Answer:

Required equation is = k [ x² +6x -16]

Step-by-step explanation:  

Given zeros of the equation 2 and - 8  

Let the given zeros α = 2 and β = - 8

sum of the zeros  α + β  = 2 +(-8) = 2- 8 = -6

product of the zeros αβ = 2(-8) = - 16

⇒ the quadratic equation with sum of the zeros and product of the zeros

=  k [ x² - (α + β)x + αβ ]  

=  k [ x² - (-6)x + (-16) ]  

=  k [ x² +6x -16]

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