quadratic polynomial,whose zeros r 2 and -8
Answers
Answered by
2
Answer:
Required equation is = k [ x² +6x -16]
Step-by-step explanation:
Given zeros of the equation 2 and - 8
Let the given zeros α = 2 and β = - 8
sum of the zeros α + β = 2 +(-8) = 2- 8 = -6
product of the zeros αβ = 2(-8) = - 16
⇒ the quadratic equation with sum of the zeros and product of the zeros
= k [ x² - (α + β)x + αβ ]
= k [ x² - (-6)x + (-16) ]
= k [ x² +6x -16]
Similar questions