Question

Quadratic polynomial x2
+ 3x – 5 has zeroes as ∝ and (beta). Now form a quadratic
polynomial whose zeroes are (i)3∝ – 1, 3 – 1 (ii) ∝
^2+ 1,
^2 + 1​

Answer 1

Answer:

α and β are the root of the equation

ax^2 +bx + c =0 , so , α + β = -b/a and αβ =c/a

Now, -1/α +(-1/β) = -{(-b/a)/c/a}=b/c

and (-1/α)(-1/β) = a/c . Hence the required quadratic equation is

x^2 -(sum of the roots)*x+product of the root=0 i.e. x^2 - (b/c)x + a/c = 0

i.e. cx^2 -bx +a =0

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Answer 2

Answer:

same of the upper answer