Math, asked by janak82, 1 year ago

quadratic polynomials:
√3x^ + 10x + 7√3

Answers

Answered by MrThakur14Dec2002
6
SOLUTION...

 \sqrt{3}  {x}^{2}  + 10x + 7 \sqrt{3}
 \sqrt{3}  {x}^{2}  + 7x + 3x + 7 \sqrt{3}
x( \sqrt{3} x + 7) +  \sqrt{3} ( \sqrt{3} x + 7)
( \sqrt{3} x + 7)(x +  \sqrt{3} )
x =  - 7 \div  \sqrt{3}  \: or -  \sqrt{3}
☆☆☆HOPE THIS WILL HELP YOU.......
Answered by kushagra210
6


hope this helps you......
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