Math, asked by kharwarrahul302, 5 months ago

quadric equation
√3n^2+10n+7√3=0​

Answers

Answered by Anonymous
2

 \sqrt{3}  {n}^{2}  + 10n + 7 \sqrt{3} = 0  \\  \\  =  >  \sqrt{3}  {n}^{2}  + 3n + 7n + 7 \sqrt{3}  = 0 \\  \\  =  >  \sqrt{3}n(n +  \sqrt{3}  ) + 7(n +  \sqrt{3} ) = 0 \\  \\  =  > (n +  \sqrt{3})( \sqrt{3} n + 7) = 0

Required values of n :

 -  \sqrt{3}  \: and \:  \frac{ - 7}{ \sqrt{3} }

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