Quadric equation by factorisation
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Here's the solution:
Given, 3x² +2√5x - 5 = 0
3x² +3√5x - √5x - 5 = 0 (Splitting the middle term)
(Sum = 2√5, Product = -15)
3x(x + √5) - √5(x + √5) = 0
(3x - √5)(x + √5) = 0
x = √5/3 , x = -√5
Hence, the roots of the given equation are √5/3 or -√5
Given, 3x² +2√5x - 5 = 0
3x² +3√5x - √5x - 5 = 0 (Splitting the middle term)
(Sum = 2√5, Product = -15)
3x(x + √5) - √5(x + √5) = 0
(3x - √5)(x + √5) = 0
x = √5/3 , x = -√5
Hence, the roots of the given equation are √5/3 or -√5
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