Quadrilateral A B C D is shown. Sides A D and B C are parallel. Sides A B and C D are congruent. Angle A is 115 degrees. What is the measure of ADC in quadrilateral ABCD? 45° 65° 115° 135°
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Answer:
65° if its a parallelogram
115° if its a trapezoid
Step-by-step explanation:
Since i don't see a diagram attached there are two possible answers.
Answer 1. The quadrilateral in parallelogram.
In this case ∠A and ∠D sum up to 180°, therefore:
∠ADC = 180° - 115° = 65°
Answer 2. The quadrilateral is isosceles trapezoid.
In this case ∠A is congruent with ∠D, therefore:
∠ADC = ∠A = 115°
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