Math, asked by emilylomeli7714, 5 months ago

Quadrilateral A B C D is shown. Sides A D and B C are parallel. Sides A B and C D are congruent. Angle A is 115 degrees. What is the measure of ADC in quadrilateral ABCD? 45° 65° 115° 135°

Answers

Answered by fsefe2008
2

Answer:

65° if its a parallelogram

115° if its a trapezoid

Step-by-step explanation:

Since i don't see a diagram attached there are two possible answers.

Answer 1. The quadrilateral in parallelogram.

In this case ∠A and ∠D sum up to 180°, therefore:

∠ADC = 180° - 115° = 65°

Answer 2. The quadrilateral is isosceles trapezoid.

In this case ∠A is congruent with ∠D, therefore:

∠ADC = ∠A = 115°

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