quadrilateral ABCD is a rhombus, diagonal AC and BD intersect each other in point T.
Prove that:AB²+BC²+AD²=AC²+BD²
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LHS=AB² + BC² + CD² + DA² = [math]4L^2[/math] RHS=AC² + ... AC and BD are its two diagonals intersecting at O. How do you prove that AB² + BC² ... How can I prove that these points are in a straight line?
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