Quadrilateral ABCD is cyclic .If angle B = (5x-4)° and angle D = (4x-5)° . Then measure of B =?
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ANSWER:
101
EXPLANATION:
ABCD IS CYCLIC QUAD
THEREFORE
angle B + angle D = 180
5x-4 + 4x -5. = 180
9x-9 =180
x-1 =20
x=21
angle B = 5(21) - 4
= 105 -4
= 101
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