Quadrilateral ABCD is inscribed in this circle. What is the measure of angle A? Enter your answer in the box. ° A quadrilateral inscribed in a circle. The vertices of the quadrilateral lie on the edge of the circle and are labeled as A, B, C, D. The interior angle A is labeled as left parenthesis x minus 36 right parenthesis degrees. The angle B is labeled as 28 degrees. The angle D is labeled as x degrees.
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3
Answer:
m∠A = 116°
Step-by-step explanation:
For better understanding of the solution, see the attached figure of the problem :
The quadrilateral ABCD is inscribed in a circle, Thus the quadrilateral ABCD is a cyclic quadrilateral.
Also, Sum of opposite angles of a cyclic quadrilateral is supplementary.
Now, m∠A = (x - 36)°, m∠B = 28° and m∠D = x°
But, since the sum of opposite angles is 180°
⇒ 28° + x° = 180°
⇒ x = 180 - 28
⇒ x = 152
So, m∠A = (x - 36)°
⇒ m∠A = (152 - 36)°
⇒ m∠A = 116°
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Answered by
3
Answer:
116°
Step-by-step explanation:
A quadrilateral inscribed in a circle
so opposite angles will have sum = 180°
∠B + ∠D = 180°
∠B = 28°
∠D = x°
28° + x° = 180°
=> x° = 152°
∠A = (x - 36)°
∠A = x° - 36°
∠A = 152° - 36°
∠A = 116°
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