quadrilateral ABCD is parallelogram. if angle A =x° and angle B=2x° then angle C =?
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Answer:
A = x°
B=2x°
let C and D = x°
x°+2x°+x°+x°=360°
5x°=360°
x° = 360/5
x° = 72°
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Angles are :-
Angle A = 72°
Angle B = 2×72° = 144°
Angle C = 72°
Angle D = 72°
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Let's check :-
72°+144°+72°+72°
= 360°
Hence, answer is correct
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