quadrilateral abcd where ab=5cm, bd=6cm, cd=5.8cm, da=4.3cm, bc=5.5cm
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Answer:
- draw the diagnols BD of length 6cm.
- with B as centre draw an arc of radius 5.5cm.
- also, with D as centre draw an arc of length 5.8cm and cut the previous arc.
- the point of intersection is named as C and join BC and DC.
- again, with B as centre draw an arc of length 5cm.
- also, with D as centre draw an arc of length 4.3cm and cut the previous arc.
- the point of intersection of these two arcs is named as A.
- join BA and DA. hence quadrilateral ABCD is obtained.
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