Question

quadrilateral
figure in
PQRS
which
RO
area
k) Find the
given in
of the
the adjoining
= 12 cm
3RB = 2PA = QS​

Answer 1

Answer:

thanku for free points

Answer 2

Area of quadrilateral=Area of ΔPSR+Area of ΔPQR

Given PR=20cm,SA=10cm,QB=12cm

=[

2

1

×PR×SA]+[

2

1

×PR×QB]

=

2

1

×20×10+

2

1

×20×12

=100+120

=220cm

2

.

solution