Math, asked by amankoli1272, 3 months ago

Quadrilateral mrpn is a cyclic angle r= (5x+13)degree,angle n=(4x+4)degree find meaasure of n and r

Answers

Answered by Anonymous
13

Correct Question :-

□MRPN is a cyclic quadrilateral, ∠R = (5x-13)° and ∠N=(4x+4)° then find measure of ∠R and ∠N.

To Find :-

  • The measure of ∠R and ∠N.

Solution :-

Given,

  • □ MRPN is cylic quadrilateral.
  • ∠R = (5x - 13)°
  • ∠N = (4x + 4)°

We know that,

The sum of either pair of opposite angles of a cylic quadrilateral is 180°.

⟹ ∠R + ∠N = 180°

⟹ (5x - 13)° + (4x + 4)° = 180°

⟹ 5x - 13 + 4x + 4 = 180°

⟹ 9x - 9 = 180°

⟹ 9x = 189

x = 21°

So,

  • ∠R = (5x - 13)° = (5 × 21 - 13)° = (105 - 13)° = 92°.

  • ∠N = (4x + 4) = (4 × 21 + 4)° = (84 + 4)° = 88°.

Therefore,

The measure of ∠R and ∠N is 92° and 88°.

Answered by Anonymous
18

</p><p>\large\overline{\underline{ \boxed{ \sf \red{\bigstar \: question}}}}</p><p>

Quadrilateral mrpn is a cyclic angle r= (5x+13)degree,angle n=(4x+4)degree find meaasure of n and r

</p><p>\large\overline{\underline{ \boxed{ \sf \red{\bigstar \: answer}}}}</p><p>

 \bf \ \: In \:  case \:  of  \: </h3><h3>cyclic \:  quadrilateral \:  opposite \:  \\   \bf \: angles \:  are \:  supplimentary.

∠R+∠N= {180}^{o}

9x−9= {180}^{o}

x =  {21}^{o}

∠R=5(21)−13 \\ =105−13 \\ = {92}^{o} </p><p></p><p>

∠N=4(21)+4 \\ = {88}^{o}

</p><p>\large\overline{\underline{ \boxed{ \sf {\ \:  the \: values \: are \:  {92}^{o} and \:  {88}^{o} }}}}</p><p>

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