Question

quadrilateral PMNQ.
(c) An exhibition tent is in the form of a cylinder surmounted by a cone. The height of the tent above
the ground is 85m and the cylindrical part is 50m. If the diameter of the base is 168m. Find the
quantity of canvas required to make the tent. Find the length of the canvas, given that width is 2m.​

Answer 1

Total height of the tent = 85 m

Diameter of the base = 168 m

Therefore, radius (r) = 84 m

Height of the cylindrical part = 50 m

Then height of the conical part = (85 - 50) = 35 m

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