Quadrilateral PQRS is a rhombus. If PQ=10 and PR=16 therefore QS=____. *
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Answered by
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Answer:
Let the point of intersection of the diagonals of the rhombus be denoted by the point O
PO=
2
PR
=12cm
QO=
2
QS
=9cm
PQ=
PO
2
+OQ
2
=
12
2
+9
2
=
144+81
=
225
=15.cm
∴ side = 15 cm
∴ Perimeter = 4(side) = 60 cm.
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