quadrilateral pqrs . T,U are points on PS,RS respectively. angle PQT= angleRQU. angleTQS=angleUQS. prove QT=QU
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RU+∠UQS
In △PQS and △RQS,
PQ=QR (given)
∠PQS=∠RQS
[ ∵∠PQT=∠RQU &
∠TQS=∠UQS
∴∠PQT+∠TQS=∠RQU+∠UQS
∠PQS=∠RQS ]
QS=QS [common]
∴△PQT≅△RQS [By SAS]
∠PSQ=∠QSR [By CPCT] →(1)
Now, in △QTS △QSU
QS=QS (common)
∠TQS=∠SQU [given]
∠TSQ=∠USQ [from (1)]
∴△QTS≅△QSU
∴QT=QU [By CPCT]
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