quadrilateral rhombus question
Attachments:
Answers
Answered by
0
Rhombus all 4 sides are equal
X+X+X+x = 104
4x = 104
x=26cm
Now diagonals of rhombus bisects each other at 90° then
26^2 = (5x)^2+(12x)^2
676 = 25x^2+144x^2
676 = 169x^2
X^2 = 676/169
x^2 = 4
X=2
Hence 5*2=10 and 12*2=24 ....Hence full length of the diagonals are 10+10=20 and 24+24=48.
Hope it help you.
X+X+X+x = 104
4x = 104
x=26cm
Now diagonals of rhombus bisects each other at 90° then
26^2 = (5x)^2+(12x)^2
676 = 25x^2+144x^2
676 = 169x^2
X^2 = 676/169
x^2 = 4
X=2
Hence 5*2=10 and 12*2=24 ....Hence full length of the diagonals are 10+10=20 and 24+24=48.
Hope it help you.
jasveersinghrap7f82w:
grt keep it up... !
Thank you
yhhh wlc...!
ur class..
Answered by
0
hope the answer shall help u...if so plz mark it brilliant
Attachments:
Similar questions