quadritic equation
(x+1)^2=2(x-3)
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Answer:
x²+1+x=2x-3
x²+x-2x+1+3=0
x²-x+4=0
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Step-by-step explanation:
Answered by
0
Step-by-step explanation:
We will use identity (a+b)²=a²+2ab+b²
so (x+1)²=x²+2x+1
and 2(x-3) =2x-6
so x²+2x+1=2x-6
x²+1=-6
x²+1+6=0
x²+7=0
x=root-7
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