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show that every positive integer is of the form to 2m and that every positive odd integer is of the form 2m+ 1 where m is some integers.

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Answered by subhalaxmiswain123
1

Answer:

Let n be an arbitrary positive integer. On dividings n by 2, let m be the quotient and r be the remainder. n = 2m or ( 2m+1) ,for some integre m. ... Hence, every positive ever integer is of the form 2m and every positive odd integer is of the form ( 2m +1) for some integer m.

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