#Quality Question.
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Q. Solve This Linear Equation in two Variables.
Answers
Solution :-
Given,
Then, Take 1/x = a, 1/y = b.
The given Comes,
- 2a +5b = 1 .... Eq -1
- 60a + 40b = 19 ....Eq -2
Let us eliminate 'u' From Eq -1 and 2.
Multipliply Equation 1 By 60 and Equation 2 by 2,
We get :-
- 120a + 300b = 60.... Eq -3
- 120a + 80b = 38....Eq -4
Substract Eq 4 and Eq 3. We get :-
120a + 300b = 60
120a + 80b = 38
______________
200b = 22
b = 22/220
b = 10.
Step-by-step explanation:
Given,
\frac{2}{x} + \frac{5}{y} = 1 \: \: and \: \: \frac{60}{x} + \frac{40}{y} = 19x2+y5=1andx60+y40=19
Then, Take 1/x = a, 1/y = b.
The given Comes,
2a +5b = 1 .... Eq -1
60a + 40b = 19 ....Eq -2
Let us eliminate 'u' From Eq -1 and 2.
Multipliply Equation 1 By 60 and Equation 2 by 2,
We get :-
120a + 300b = 60.... Eq -3
120a + 80b = 38....Eq -4
Substract Eq 4 and Eq 3. We get :-
120a + 300b = 60
120a + 80b = 38
______________
200b = 22
b = 22/220
b = 10.