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Q. Solve This Linear Equation in two Variables.
$\frac{2}{x} + \frac{5}{y} = 1 \\ \frac{60}{x} + \frac{40}{y} = 19\ \textless \ br /\ \textgreater$
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Answer 1

Solution :-

Given,

$\frac{2}{x} + \frac{5}{y} = 1 \: \: and \: \: \frac{60}{x} + \frac{40}{y} = 19$

Then, Take 1/x = a, 1/y = b.

The given Comes,

• 2a +5b = 1 .... Eq -1
• 60a + 40b = 19 ....Eq -2

Let us eliminate 'u' From Eq -1 and 2.

Multipliply Equation 1 By 60 and Equation 2 by 2,

We get :-

• 120a + 300b = 60.... Eq -3
• 120a + 80b = 38....Eq -4

Substract Eq 4 and Eq 3. We get :-

120a + 300b = 60

120a + 80b = 38

______________

200b = 22

b = 22/220

b = 10.

Answer 2

Step-by-step explanation:

Given,

\frac{2}{x} + \frac{5}{y} = 1 \: \: and \: \: \frac{60}{x} + \frac{40}{y} = 19x2+y5=1andx60+y40=19

Then, Take 1/x = a, 1/y = b.

The given Comes,

2a +5b = 1 .... Eq -1

60a + 40b = 19 ....Eq -2

Let us eliminate 'u' From Eq -1 and 2.

Multipliply Equation 1 By 60 and Equation 2 by 2,

We get :-

120a + 300b = 60.... Eq -3

120a + 80b = 38....Eq -4

Substract Eq 4 and Eq 3. We get :-

120a + 300b = 60

120a + 80b = 38

______________

200b = 22

b = 22/220

b = 10.