Question

Quality Question
@Differentiation
If , x = cos2\theta + 2cos\theta \ y = sin2\theta - 2sin\theta
x= cos2θ+2cosθ
y=sin2θ−2sinθ
​

the calculate dy/dx​

Answer 1

x=cos2θ+2cosθ

=>dx/dθ= -2sin2θ-2sinθ

y=sin2θ-2sinθ

dy/dθ=2cos2θ-2cosθ

hance,

dy/dx= - (cos2θ-cosθ)/(sin2θ+sinθ)