Physics, asked by Anonymous, 1 month ago

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If k.e of two balls before inelastic collision is 50 j after collision each ball loses 10j what is the percent of energy wash ball loses after collision​.

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Answers

Answered by sarfrajwarsi350
0

Answer:

Solution

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(a)No

K.E. is not conserved during the given elastic collision, K.E. before and after collision is the same. In fact, during collision, K.E. of the balls gets converted into potential energy.

(b) Yes.

Linear momentum is always conserved, no matter what.

(c) In an inelastic collision, there is always a loss of kinetic energy, i.e., the total kinetic energy of the billiard balls before collision will always be greater than that after collision.

The total linear momentum of the system of billiards balls will remain conserved even in the case of an inelastic collision.

(d) Elastic

In the given case, the forces involved are conserved. This is because they depend on the separation between the centres of the billiard balls. Hence, the collision is elastic.

Answered by anusujasree
1

(a)No

K.E. is not conserved during the given elastic collision, K.E. before and after collision is the same. In fact, during collision, K.E. of the balls gets converted into potential energy.

(b) Yes.

Linear momentum is always conserved, no matter what.

(c) In an inelastic collision, there is always a loss of kinetic energy, i.e., the total kinetic energy of the billiard balls before collision will always be greater than that after collision.

The total linear momentum of the system of billiards balls will remain conserved even in the case of an inelastic collision.

(d) Elastic

In the given case, the forces involved are conserved. This is because they depend on the separation between the centres of the billiard balls. Hence, the collision is elastic.

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