Question

Quantitative aptitude

Answer 1

very tough question.

Answer 2

Answer:  The correct options are

51.   (4) 216.

52.  (5) None of these.

53.  (3) $7\dfrac{7}{9}.$

Step-by-step explanation:  We are given to simplify the following three algebraic expressions :

Solution to 51 :  We have

$E+1\\\\\\=\dfrac{3}{1}\times88\%\times900\\\\\\=\dfrac{3}{11}\times\dfrac{88}{100}\times900\\\\\\=\dfrac{3}{11}\times792\\\\ =3\times72\\\\=216.$

The correct option is (4) 216.

Solution to 52 :  We have

$(7)^4\div(49)^3\times343\\\\=7^4\div7^{2\times3}\times7^3\\\\=\dfrac{7^4}{7^6}\times7^3\\\\=7^{4-6}\times7^3\\\\=7^{-2}\times7^3\\\\=7^{-2+3}\\\\=7^1\\\\=7^{3-2}.$

The correct option is (5) None of these.

Solution to 53 :  We have

$E_3\\\\\\=\dfrac{105}{51}\times\dfrac{88}{24}\times\dfrac{34}{33}\\\\\\=\dfrac{35}{51}\times\dfrac{11}{3}\times\dfrac{34}{11}\\\\\\=\dfrac{70}{9}\\\\\\=7\dfrac{7}{9}$

The correct option is (3) $7\dfrac{7}{9}.$