Quantitative Aptitude
Directions (Q. 11 - 12): Refer to the data below and answer the questions that follow
Five heavy weight boxers measure their weights. Following results were obtained
L P is heavier than R by 14 kg and B is lighter than by 10 kg.
IL M's weight is equal to the average weight of the four other boxers.
IIL P's weight and B's weight taken together equals the weight of M and S.
IV. The sum of the weights of all five boxers is 520 kg.
11. What is the average of the weights of M and R?
(A) 102 kg
(B) 104 kg
(9) 100
(D) 98 kg
12. What is the average of the weights of P, S and B ?
(A) 102.3 kg
(B) 1073 kg V105.3 kg (D) 1153 ks
Answers
Answer:
11)(A) 102 kg
12)(C) 105.3 kg
Step-by-step explanation:
Before going to answer your Question there is a small correction in the Question
In point I B is lighter than S by 10 kg
Given,
I)P is heavier than R by 14 kg and B is lighter than S by 10 kg.
P-R=14 kg
P=R+14
S-B=10 kg
S=B+10
II) M's weight is equal to the average weight of the four other boxers.
M=P+B+R+S/4
III)P+B=M+S
IV)P+B+R+M+S=520
From IV) P+B+R+S=520-M
M=P+B+R+S/4 substitute above Equation in this Equation
M=520-M/4
4M=520-M
5M=520
M=104
From III)P+B=M+S we can write P+B-S=M
P+B-S=104
substitute P=R+14,S=B+10 in the above Equation
R+14+B-B-10=104
R+4=104
R=100
P=R+14 substitute R=100
P=100+14
P=114
11) What is the average of the weights of M and R?
The average of M+R is 100+104=204
204/2=102 kg
From IV) P+B+R+S=520-M
P+B+R+S=520-104
we know,P=114 and R=100
114+B+100+S=416
B+S=416-214
B+S=202
we know S=B+10
B+B+10=202
2B=202-10
2B=192
B=96
by taking IV) P+B+R+S=520-M
114+96+100+S=416
S=416-310
S=106
12) What is the average of the weights of P, S and B ?
P=114,S=106,B=96
114+106+96/3=105.3 kg