Question

Quantitative Aptitude
Question 6 of 20
Pure diesel costs Rs 68 per litre. A dealer adulterated it with kerosene costing Rs 13 per litre and made a profit of 25% by selling the mixture
at Rs 60 per litre In what ratio did he mix kerosene and pure diesel?
7:4
3:7
7;3
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Answer 1

Answer:

The ratio in which kerosene to pure diesel mix up is 7 : 5

Step-by-step explanation:

Given as :

The cost of pure diesel = Rs 68 per liters

The cost of kerosene = Rs 13 per liters

The profit after mixing = 25%

The selling price of mixture = Rs 60 per liters

Let The ratio of kerosene to diesel = x : y

According to question

Applying the rule of alligation

The cost price of mixture oil = c.p = $\dfrac{100}{100 + 25}$ × s.p of mixture

Or, c.p pf mixture = $\dfrac{100}{125}$ × Rs 60

Or, c.p  of mixture = Rs 48

Again

The ratio of mixture = $\dfrac{c.p of mixture - c.p of kerosene}{c.p of diesel - c.p of mixture}$

Or, x : y = $\dfrac{48 - 13}{68 - 48}$

Or, $\dfrac{x}{y}$ = $\dfrac{35}{20}$

Or, x : y = 7 : 5

So, The ratio of kerosene to diesel = x : y = 7 : 5

Hence, The ratio in which kerosene to pure diesel mix up is 7 : 5  Answer