quantity of electricity required to reduce 1 mol nitrobenzene to aniline
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123 g of nitrobenzene use 6 moles electron for complete reduction. Therefore the amount of charge required = 57900 x 2 = 115800 C.
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Explanation:
Reaction for reduction :
C6H5NO2+6H++6e−⟶C6H5NH2+2H2O
Given, molar mass of C6H5NO2=123
Here, 12.3 g nitrobenzene mole =1236×12.3=0.6
Charge =0.6×96500 coloumbs
=57900
Efficiency =50%
⇒ 2×57900= coloumbs
∴ charge required is 115800 coloumbs.
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