Question

Quantity of nitrogen is 4 times the Quantity of Oxygen in air. The
amount of oxygen in 25 liter
of air, will be? ​

Answer 1

Step-by-step explanation:

Ideal gas equation is given by

pV=nRT ...(i)

For oxygen, p=1atm,V=1L,n=n

0

Therefore equation (i) becomes

∴1×1=n

o

2

RT

⇒n

o

2

=

RT

1

For nitrogen p=0.5atm,V=2L,n=nN

∴0.5×2=n

N

2

RT

⇒n

N

2

=

RT

1

For mixture of gas

p

mix

V

mix

=n

mix

RT

Here, n

mix

=nO+n

N

2

∴

RT

p

mix

V

mix

=

RT

1

+

RT

1

⇒p

mix

V

mix

=2

i hope it's helpful to u❤

Mark me as brainlist