Quantity of x is increased by 10% and it is 500 now ? find the x
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>>Earlier value of the article = x.
Increase in 10% = 10% of x . = 10/100×x = x/10.
The quantity after increasing = x + x/10 = 10x+x/10=11x/10.
ATQ, 11x/10 = 500.
or 11x = 500 × 10.
or x = 500 × 10 / 11.
Therefore x = 545.5(approx.) = 546 (rounding off)
Therefore the value of x is 546.
Increase in 10% = 10% of x . = 10/100×x = x/10.
The quantity after increasing = x + x/10 = 10x+x/10=11x/10.
ATQ, 11x/10 = 500.
or 11x = 500 × 10.
or x = 500 × 10 / 11.
Therefore x = 545.5(approx.) = 546 (rounding off)
Therefore the value of x is 546.
Greta:
no its a wrong answer
Answered by
2
Answer:
Step-by-step explanation:
10% of x is increased.
So, increase = 10x/100
ATQ,
If x is increased by 10% value becomes 500.
So, equation would be:
=> x+10x/100 = 500
=> 100x+10x/100 = 500
=> 110x = 500*100
=> 110x = 50000
=> x = 50000/110
=> x = 454.55 approx
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