Question

Quantum no are possible for how many orbitals n=3 , l=2 , m=2

Answer 1

hey buddy here is your answer by UDIT

n= 3 is possible for s p and d orbitals

l=2 is possible for d

m=2 is possible for d (z^2)

hence the answer is only 1 orbital that is d (z^2)

thanks

Answer 2

Hope u like my answer.
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=> n represents the principle Quantum number and gives the number of shell electron present in or say in which period it is present in.

Here, n = 3, so the electron is present in 3rd period.

=> l represents the azimuthal Quantum number and derives the orbital within the period...
the value of l, for s =0, for p =1, for d =2.

Here,l =2, it states that the electron is in d orbital.

=>m represents magnetic Quantum number and it derives the position of electron within shell.

As per d - orbital, there are 5 distinctive parts in which a pair of electrons can be stored.

The value of m for each distinctive part will be like - 2,-1,0,1,2..and are named as

$= > \bf d_{xy}, d_{yz}, d_{xz}, d_{ {x}^{2} - {y}^{2} }, d_{ {z}^{2} }$
Respectively.

Here m = 2 so, the electrons lies in

$= > \bf \: 3d_{ {z}^{2} } \: \: \: \: orbital$
Since the same configurations can't be of different position in same element..

So, this is possible for only 1 orbital and for 2 electrons.
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