Question

Quantum numbers and electron configuration iit jee

Answer 1

Electronic configuration of Rb = 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s1

Check that there are 37 electrons.

Therefore,

Principal quantum number, n = 5

Azimuthal quantum number, l = 0 (since for s orbital l = 0)

Magnetic quantum number, m = 0 (since for l = 0, there is only one m value i.e. 0)

Spin quantum number, s = +½ or -½ (there is only one electron and it can have clockwise or anticlockwise spins)..

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