Question

Quartile deviation of 6 numbers 15, 8, 36 ,40, 38, 41 is equal to​

Answer 1

Answer:

Formally, the Quartile Deviation is equal to the half of the Inter-Quartile Range and thus we can write it as – Q d = Q 3 – Q 1 2 Q_d = \frac{Q_3 – Q_1}{2} Qd=2Q3–Q1 Therefore, we also call it the Semi Inter-Quartile Range.

Answer 2

Quartile deviation = 2.

• One way to quantify dispersion is by quartile deviation. Recalling quartiles and their definitions will help us grasp them better before moving on. A list of numerical data is divided into three quarters by the values known as quartiles, such as Q1, Q2, and Q3.
• The central portion of the three quarters measures the point of distribution's centre and displays data values that are close to the midway (or the central value; this is referred to as the median). Only half of the information set is represented by the lower half of the quarters, which is below the median, while the upper half is represented by the top half, which is above the median. The distribution or dispersion of the provided data set is thus represented by the quartiles.

Here, the data is given as,

15, 8, 36 ,40, 38, 41.

Now, $Q_{1} =36$ and $Q_{3} =40$.

Then, $\frac{Q_{3}-Q_{1} }{2} =\frac{4}{2} = 2$.

Hence, Quartile deviation = 2.

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