Question

quatratic polynomial 2x²-3x+1 has zeros as alpha and beta now form a quadratic polynomial whose zeros are 3 alpha and 3 beta​

Answer 1

Step-by-step explanation:

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Answer 2

The equation x2−3x−2=0x2−3x−2=0 has 3/2+√17/23/2+√17/2 and 3/2−√17/23/2−√17/2 as it's solutions.

Now, let Alpha = 3/2+√17/23/2+√17/2

And, Beta = 3/2−√17/23/2−√17/2

Hence, 2 Alpha/Beta = p = 2(3+√17)/(3−√17)=2(3+√17)/(3−√17)=

2[(3+√17)2]/(−8)=−(26+√17)/42[(3+√17)2]/(−8)=−(26+√17)/4

And, 2 Beta/Alpha = q = 2(3−√17)/(3+√17)=2(3−√17)/(3+√17)=

2[(3−√17)2]/(−8)=−(26−√17)/42[(3−√17)2]/(−8)=−(26−√17)/4