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11.
The sum of the digits of a two-digit number is 12. The number obtained
by interchanging its digits exceeds the given number by 18. Find the
number.
[CBSE 2006
Answers
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2
Answer:
Answer=57
Step-by-step explanation:
Let the number at ones place be k
Number at tens place=12-k, because there sum is 12
Now original number=10(12-k)+k
120-10k+k=120-9k , it is original number
Now interchanged number=10k+12-k
9k+12, this is interchanged number
Now A/Q 9k+12-(120-9k)=18
9k+12-120+9k=18
18k=18+120-12
k=126/18
k=7
So original number=10(12-k)+k=10×5+7=57
(57)ANS.
HOPE IT WILL HELP YOU.
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