Math, asked by nandaninandani580, 4 months ago

que
11.
The sum of the digits of a two-digit number is 12. The number obtained
by interchanging its digits exceeds the given number by 18. Find the
number.
[CBSE 2006​

Answers

Answered by taqueerizwan2006
2

Answer:

Answer=57

Step-by-step explanation:

Let the number at ones place be k

Number at tens place=12-k, because there sum is 12

Now original number=10(12-k)+k

120-10k+k=120-9k , it is original number

Now interchanged number=10k+12-k

9k+12, this is interchanged number

Now A/Q 9k+12-(120-9k)=18

9k+12-120+9k=18

18k=18+120-12

k=126/18

k=7

So original number=10(12-k)+k=10×5+7=57

(57)ANS.

HOPE IT WILL HELP YOU.

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