Question

Que 3: Find dy/dx if y =sinx / (1+cos) *
O /
1/(1+sinx)
O 1/(1+ cosx)
tanx
none of these​

Answer 1

Answer:

Given, y = sin x/ (1+ cosx)

So, dy/dx= d/dx(sinx/(1+cosx))

= (1+ cosx). d/dx(sinx) - sinx . d/dx(1+cosx) /(1+cosx) ²

=(1+cosx). cosx - sinx(0 - sinx) /(1+ cosx) ²

=(cosx + cos²x + sin²x) /(1 + cosx) ²

= (1 + cosx ) / (1 + cos x) ²

=1/ (1+cosx)

Therefore, dy) dx = 1/ (1+cosx)