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4. Form a continuous frequency distribution table for the marks obtained by 30 students in
a X std public examination.
328, 470, 405, 375, 298, 326, 276, 362, 410, 255, 391, 370, 455, 229, 300, 183, 283, 366, 400,
495, 215, 157, 374, 306, 280, 409, 321, 269, 398, 200.
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Step-by-step explanation:
Given Form a continuous frequency distribution table for the marks obtained by 30 students in a X std public examination.
328, 470, 405, 375, 298, 326, 276, 362, 410, 255, 391, 370, 455, 229, 300, 183, 283, 366, 400, 495, 215, 157, 374, 306, 280, 409, 321, 269, 398, 200.
- So we have minimum and maximum marks in this frequency distribution
- So maximum marks will be 495
- So minimum marks will be 157
- Now Range = Maximum marks – Minimum marks
- = 495 – 157
- = 338
- So Range / class size = 338 / 50
- = 6.76
- = 7 (approx.)
- So taking the class size as 50 we get
- 150 – 200 2
- 200 – 250 3
- 250 – 300 6
- 300 – 350 5
- 350 – 400 7
- 400 – 450 4
- 450 – 500 3
- So total 30
Reference link will be
https://brainly.in/question/6897998
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