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net resistance of R1 and R2 = 2ohm
total resistance in the circuit = 1+2 = 3 ohm
current = V/R = 3A
current in the resistor R2 = 3×2/3 = 2 A
power= I²Rt = 2²×3×60 = 7200 J
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total resistance in the circuit = 1+2 = 3 ohm
current = V/R = 3A
current in the resistor R2 = 3×2/3 = 2 A
power= I²Rt = 2²×3×60 = 7200 J
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Krais:
Plz tell me.....
look we can find current along a particular resistor by multiplying the initial current to the parallel resistance and then by dividing it by the sum of both resistances in this case it is 3×6/(3+6). = 3*2/3 it is known as current divider formula u can learn it to from youtube
Thanks a lot frnd
I got it
ur wlcm
But 4 x3 x60 = 720
hmm it must be 720
yes
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