Question

Que. 9 In A ABC, DE II BC. Find X
plz paper solution
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Answer 1

according to thales theorem , we have

$\frac{x}{x + 1} = \frac{x + 3}{x + 5}$

$x(x + 5) = (x + 1)(x + 3)$

${x}^{2} + 5x = {x}^{2} + 4x + 3$

$x = 3$

hope it helps you:)