Question

Que.9. The velocity-time graph of an object moving along
a straight line is shown in Fig. 1.28. Obtain the distance covered by
the object between (a) t = 0 s to t = 10 s, and (b) t = 0 s to t = 20 s.
00
-Velocity v (m 6-1)
10
Time t(s)
Fig. 1.28​

Answer 1

Area of velocity time graph gives displacement

So displacement covered in time interval t=0 to t=10 is area of triangle OBD=1/2(AD×BD) =1/2(10×8)=40units

Displacement in the interval t=10 to t=20 is area of triangle CBD=1/2(CD×BD)=1/2(10×8)=40 units